Calculation of material requirements to make no floor size 6m x 13m
Hello fellow ilmusipil, this time someone asked about the calculation of material requirements to make no reinforced concrete floor size 6m x 13 m, the question is posed by Bp. Ilham Berto will we answer together, may be a bit of enlightenment, as well as an example for other colleagues who happen to have the same problem, ok this is a question the answer :-)Question = "Punten skipper .... I want ngedak upstairs, size 6m x 13m, approximately takes how many bags of cement? how m3 of sand? How m3 of gravel? how ideal and powerful composition between 3 to the material?
where cheaper between ngecor themselves by purchasing so of adimix for example?
thank you..."Answer = previously been we make an example of how to calculate the needs DAK concrete floor per m2, so that we can apply the description of the calculation to calculate the total requirement DAK concrete floor size 6m x 13m, but note that in the work of DAK is also a structural beam, so we will count also with the other formula.DAK picture concrete floor 6m x 13m
Floor plate concrete structure
12 cm thick slab, reinforcement D10-2OO means dimater 10mm post spacing of 20cm, the following calculation of material requirements
a). Concrete = 6m x 13m x 0,12m = 9,36m3.
b). mix cement: sand: gravel = 1pc: 2ps: 3kr
c) .Semen = (1/6 x 9,36m3) / 0,024 = 65 sacks (if one 50kg sack of cement containing no 0,024m3)
d). Sand = 2/6 x 9,36m3 = 3,12 m3
e). gravel = 3/6 x 9,36m3 = 4,68m3
f). Iron D10 = ((6m / 0.2) * 13m * 2BH) + ((13m / 0.2) * 6m * 2BH) = 1560m, 1 iron bar = 12m, so the total requirement of iron = 1560m / 12m = 130 rods.
Structural beams for concrete
Beam size of 15cm x 30cm, the principal reinforcement 6D10, meaning that 6 pieces of 10mm diameter iron, and iron begel D8-200 means iron 8mm diameter 20cm distance pairs
a). Total length of the beam = (6BH x 6m) + (3BH x 13m) = 75m
b). Concrete = 0,15m x 0,30m x 75m = 2,7m3
c). Cement = (1/6 x 2,7m3) / 0,024 = 19 sacks (if one 50kg sack of cement containing no 0,024m3)
d). Sand = 2/6 x 2,7m3 = 0.9 m3
e). gravel = 3/6 x 2,7m3 = 1,35m3
f). steel reinforcement staple D 10 = 6BH x 75m = 450m, iron needs D10 = 450m / 12m = 38 stalk
g). begel iron D8, length 1 begel = 0.1 + 0.1 + 0.25 + 0.25 + 0.05 + 0.05 = 0.8 m,
h). number begel = 75m / 0.2 m = 375, the total length of iron begel = 0.8 m x 375 bh = 300m, needs begel = 300m / 12m = 25 stalk
So the total material requirements for DAK concrete floor 6m x 13m
a). Zak cement = 65 + 19 = 84 zak zak
b). Sand = 3.12 m3 + 0.9 m3 = 4.02 m3
c). Gravel = 4.68 +1.35 m3 m3 = 6,03 m3
d). Iron stalk D10 = 130 + 38 = 168 stalk stalk
e). Iron D8 = 0 + 25 stalk stalk stalk = 25
Thus the simple answer is, subsequently to be clearer then we make a separate article about the comparison which is cheaper costs among themselves by using a concrete stirring instant as Adhimix, if there is a correction or additional answers can be discussed here, may be useful :-)
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